(10)=-16t^2+1700

Solution for (10)=-16t^2+1700 equation:

(10)=-16t^2+1700

We move all terms to the left:

(10)-(-16t^2+1700)=0

We get rid of parentheses

16t^2-1700+10=0

We add all the numbers together, and all the variables

16t^2-1690=0

a = 16; b = 0; c = -1690;
Δ = b2-4ac
Δ = 02-4·16·(-1690)
Δ = 108160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108160}=\sqrt{10816*10}=\sqrt{10816}*\sqrt{10}=104\sqrt{10}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-104\sqrt{10}}{2*16}=\frac{0-104\sqrt{10}}{32}
=-\frac{104\sqrt{10}}{32}
=-\frac{13\sqrt{10}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+104\sqrt{10}}{2*16}=\frac{0+104\sqrt{10}}{32}
=\frac{104\sqrt{10}}{32}
=\frac{13\sqrt{10}}{4}
$